SOLUTION: Two cars starts at the same time from towns760km apart and meet 4hrs later.One car travels 8km/hr faster than the car.whatdistance did each car travel in 4hrs?

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Question 1052121: Two cars starts at the same time from towns760km apart and meet 4hrs later.One car travels 8km/hr faster than the car.whatdistance did each car travel in 4hrs?
Found 2 solutions by ikleyn, advanced_Learner:
Answer by ikleyn(52775) (Show Source):
You can put this solution on YOUR website!
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Two cars starts at the same time from towns 760 km apart and meet 4 hrs later. One car travels 8 km/hr faster than the car.
What distance did each car travel in 4 hrs?
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Let u be the rate of the slower car, in km/h. Then the rate of the faster car is (u+8) km/h. You have this equation 760 = 4*u + 4*(u+8)), which says that the two cars together covered the full distance of 760 km in 4 hours. Simplify and solve for "u": 8u + 32 = 760 ---> 8u = 760 - 32 = 728 ---> u = = 91 km/h. The speed of the slower car was 91 km/h. Hence, it covered 4*91 = 364 km before meeting. The second car covered 760 - 364 = 396 km.

Answer by advanced_Learner(501) (Show Source):
You can put this solution on YOUR website!
car A
speed
time
distance
Car B-fast car

time

total distance
=
=
use substitution method
=
=
Speeds of Both cars
= for CAR A
= for CAR B
Distances
= for CAR A
= for car B.
for car B
=