SOLUTION: A pharmacist has an 18% alcohol solution. How much of this solution and how much water must be mixed together to make 10 liters of a 12% alcohol solution?

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Question 1019101: A pharmacist has an 18% alcohol solution. How much of this solution and how much water must be mixed together to make 10 liters of a 12% alcohol solution?
Found 2 solutions by jorel555, ikleyn:
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=amount of 18% solution; then:
.18(10-x)=.12(10)
1.8-.18x=1.2
.18x=.6
x=.6/.18=3.33
10-3&1/3=6&2/3 liters of .18 solution + 3&1/3 liters water equals 10 liters of 12% solution!!!!!!!!!!!!!

Answer by ikleyn(52765) About Me  (Show Source):
You can put this solution on YOUR website!
.
A pharmacist has an 18% alcohol solution. How much of this solution and how much water must be mixed together
to make 10 liters of a 12% alcohol solution?
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Let x be an amount (the volume in liters) of the 18% solution needed.

Then the water volume is 10-x liters.

The "pure alcohol" contents equation is

0.18*x = 0.12*10.

Solve it for x:

0.18x = 1.2   --->  x = 1.2%2F0.18 = 6.667.

Hence, 6.667 = 62%2F3 liters of the original 18% alcohol solution should be used.

Then the volume of water is 10 - 62%2F3 = 31%2F3 liters.

Answer. 62%2F3 liters of the 18% alcohol solution and 31%2F3 liters of water.