SOLUTION: Julio constructed a platform for a bean bag toss game. The plans for the original platform had dimensions of 3 feet by 5 feet. He made his platform larger by adding x feet to the l

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Question 1016040: Julio constructed a platform for a bean bag toss game. The plans for the original platform had dimensions of 3 feet by 5 feet. He made his platform larger by adding x feet to the length and width. The area of the new platform is 35 square feet. Write a quadratic equation that represents the area of his platform, and find the dimensions of the platform Julio made.
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
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x=amount added to length and width
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L=length=5ft+x; W=width=3ft+x
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LW=35ft%5E2
%285ft%2Bx%29%283ft%2Bx%29=35ft%5E2
15ft%5E2%2B8ft%2Bx%5E2=35ft%5E2
x%5E2%2B8xft%2B15ft%5E2=35ft%5E2
x%5E2%2B8xft-20ft%5E2=0 . This equation represents new area
%28x%2B10%29%28x-2%29=0
x%2B10=0 OR x-2=0
x=-10 OR x=2
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He added 2 feet to each dimension
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L=5ft+x=5ft+2ft=7ft
W=3ft+x=3ft+2ft=5ft
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ANSWER: The new dimensions were 7 feet by 5 feet.
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CHECK:
LW=35ft%5E2
%287ft%29%285ft%29=35ft%5E2
35ft%5E2=35ft%5E2