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The Doppler Shift
Problem 1While driving a car, Al honks the horn every 5 seconds. Bill is standing by the side of the road and hears the honks
of the oncoming car every 4.6 seconds. The speed of sound is 330 meters per second. Calculate the speed of Al's car.
Solution
car, t1 car, t2 Bill
------------o---------------o-----------------------o--------------
---->
The figure shows the situation.
The car moves along the straight road from the left to the right towards Bill.
At the time moment t = t1, when the distance from the car to Bill is D1, the car releases the honk.
After 5 seconds, at the t = t2 = t1+5, when the distance from the car to Bill is D2, the car releases the next honk.
The first honk arrives to the Bill location at the time moment t = .
The next honk arrives to the Bill location at the time moment t = .
The time difference between two successive honks arriving to Bill location is
- = + = 5 + .
Also, D1 - D2 = 5*v, where v is the car speed.
So, you have this equation
5 - = 4.6, or = 0.4.
Hence, v = = 26.4 m/s.
Answer. The speed of the car is 26.4 m/s or 95.04 km/h.
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