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Another unusual Travel problem (Arnold's problem on two walking old women)
(The first one is in the lesson One unusual Travel problem in this site).
Two old women started at sunrise and each walked at a constant speed. One went from A to B and the other from B to A on the same road.
They met at noon and, continuing with no stop, arrived respectively at B at 4 p.m. and at A at 9 p.m.
At what time was the sunrise that day?
Solution
Similar to the first unusual Travel problem, the distance is not a given in this problem. Nevertheless, we can solve it by applying elementary logic.
Figure 1 shows the road two old women were walking on. For simplicity, the road is shown as a straight line in the Figure 1.
Actually, it doesn't matter,  and the road might be curved :-) The point C in the Figure 1 represents the meeting point.
Let be the velocity of lady "A" moving from A to B, and let be the velocity of lady "B" moving from B to A.
Next, let t be the time (in hours) that both women spent walking from the starting moment ("the sunrise") till noon.
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Figure 1. The road between A and B
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Lady "A" covered partial way |AC| in t hours and lady "B" covered it in 9 hours. It gives the equation |AC| = = , or simply = , for short.
Similarly, lady "B" covered partial way |BC| in t hours and lady "A" covered it in 4 hours. It gives the equation |BC| = = , or simply = .
From the last two equations = * . It gives = , or = .
Now, let us consider the entire walking journey from A to B and from B to A. Lady "A" covered it in t+4 hours and lady "B" in t+9 hours. It gives the equation
= , since the distance from A to B is the same as the distance from B to A.
Simplifying it step by step, you get = = , then = , = , and, at last, = .
Thus the women were walking 6 hours before noon. It means that the sunrise was at 6:00 am that day. The problem is solved.
There is another way to complete the solution. From equations = and = you have = and = , i.e. = , or = 36 and t = = 6.
Answer. The sunrise was at 6:00 am that day.
The storyThis problem has its own story. It became known ("widely known in narrow circles") after Vladimir Arnold.
Vladimir Arnold (1937 - 2010) was the famous soviet, russian and word mathematician. In one of his interviews he remembered that this problem was given in the classroom in the Moscow school by his mathematics teacher, when he was a 6-th grade (12 years old) student. (6-th grade in soviet school at that time approximately corresponded to the 6-th - 7-th grade of American middle school). The problem was a big challenge for him. He spent the entire day trying to solve it, and was very happy when, finally, he found the solution. He memorized that impression, the problem itself and his teacher for all his life.
You can make a Google search about this story in the Internet with keywords "Vladimir Arnold problem on two walking women" if you want.
Recently this problem came in another form.
Problem 2Winnie and Piglet decided to visit one another and set off at the same time to each others house. When they met on the road
joining their houses, they forgot that they wanted to see each other and continued walking. Winnie reached Piglet's house
8 minutes after the meeting and Piglet got to Winnie's house 18 minutes after the meeting.
How long did it take Piglet to reach Pooh's house from the time he left his own house?
Solution
Let "W" be Winnie's speed and "P" be Piglet's speed.
Let "t" be the time from the start to the meeting moment.
Then you have these equations
W*t = P*18, (1) and
P*t = W*8. (2)
It implies
= , (1') ( from (1) ) and
= . (2') ( from (2) ).
Hence, = , and then = = .
Therefore, t = = 12.
In other words, it took 12 minutes from the start to the meeting moment.
Then the total time for Piglet to reach Pooh's house was 12 + 18 minutes = 30 minutes.
Answer. The total time for Piglet to reach Pooh's house was 12 + 18 minutes = 30 minutes.
My other lessons on Travel and Distance problems in this site are
Use this file/link ALGEBRA-I - YOUR ONLINE TEXTBOOK to navigate over all topics and lessons of the online textbook ALGEBRA-I.
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