SOLUTION: The first of two numbers is one more than twice the second. The sum of twice the first number and three times the second number is 51. Find the numbers.

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Question 275471: The first of two numbers is one more than twice the second. The sum of twice the first number and three times the second number is 51. Find the numbers.
Found 3 solutions by mananth, ikleyn, josgarithmetic:
Answer by mananth(16949)   (Show Source):
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The first of two numbers is one more than twice the second. The sum of twice the first number and three times the second number is 51. Find the numbers.
Let the second number be x
twice the second = 2x
1 more means 2x+1 This is the second number
twice the first number =2x
three times the second will be 3*(2x+1)
2x+3*(2x+1) = 51
2x+6x+3=51
8x=51-3
8x=48
x=6 first number
2* x= 2*6 = 12 the second number

Answer by ikleyn(53751)   (Show Source):
You can put this solution on YOUR website!
.
The first of two numbers is one more than twice the second. The sum of twice the first number
and three times the second number is 51. Find the numbers.
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        In his post, @mananth missed first and second number and produced wrong answer
        " x=6 for the first number and 2x = 2*6 = 12 for the second number ".

        I came to provide a correct and accurate solution.

Let the second number be x Twice the second = 2x One more means 2x+1. This is the first number. Twice the second number = 2x The equation for the sum of twice the first number and three times the second number is 2(2x+1) + 3x = 51. Simplify and find x 4x + 2 + 3x = 51 7x = 51 - 2 7x = 49 x = 49/7 = 7 is the second number 2*x+1 = 2*7+1 = 15 is the first number ANSWER. First number is 15; second number is 7.

Solved correctly.

Answer by josgarithmetic(39792)   (Show Source):
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The numbers
, and

First number is .