SOLUTION: A BANANNA PEEL WEIGHS 1/8 OF THE TOTAL WEIGHT OF A BANANA. IF AN UNPEELED BANANA BALANCES A PEELED BANANA OF THE SAME WEIGHT PLUS 7/8 OF AN OUNCE, HOW MUCH DOES A BANANNA WITH THE
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Question 99626This question is from textbook
: A BANANNA PEEL WEIGHS 1/8 OF THE TOTAL WEIGHT OF A BANANA. IF AN UNPEELED BANANA BALANCES A PEELED BANANA OF THE SAME WEIGHT PLUS 7/8 OF AN OUNCE, HOW MUCH DOES A BANANNA WITH THE PEEL WIEGH? I FIGURED ONE OUNCE BUT I KNOW I AM WRONG. ALSO I THINK THE EQUATION MIGHT LOOK LIKE THIS BUT IT MAY BE WRONG. 7/8X+X=1/8 OR X=1/8+7/8X PLEASE HELP THANKS. This question is from textbook
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Let x=total weight of an unpeeled banana
A banana peel weighs (1/8)x
A peeled banana weighs x-(1/8)x
Now we are told that an unpeeled banana (x) balances a peeled banana of the same weight (x-(1/8)x) plus 7/8 of an ounce. So our equation to solve is:
x=x-(1/8)x+7/8 multiply each term by 8
8x=8x-x+7 start collecting like terms
8x=7x+7 subtract 7x from both sides
8x-7x=7x-7x+7 collect like terms
x=7 oz----------------weight of an unpeeled banana
CK
7=7-(1/8)*7+7/8 multiply each term by 8
56=56-7+7
56=56
