SOLUTION: solve each equation for x x^2 + 4x + 4 = 7

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Question 99589: solve each equation for x
x^2 + 4x + 4 = 7
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2+%2B+4x+%2B+4+=+7 Start with the given equation


x%5E2+%2B+4x+-3+=+0 Subtract 7 from both sides



Let's use the quadratic formula to solve for x:


Starting with the general quadratic

ax%5E2%2Bbx%2Bc=0

the general solution using the quadratic equation is:

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29

So lets solve x%5E2%2B4%2Ax-3=0 ( notice a=1, b=4, and c=-3)

x+=+%28-4+%2B-+sqrt%28+%284%29%5E2-4%2A1%2A-3+%29%29%2F%282%2A1%29 Plug in a=1, b=4, and c=-3



x+=+%28-4+%2B-+sqrt%28+16-4%2A1%2A-3+%29%29%2F%282%2A1%29 Square 4 to get 16



x+=+%28-4+%2B-+sqrt%28+16%2B12+%29%29%2F%282%2A1%29 Multiply -4%2A-3%2A1 to get 12



x+=+%28-4+%2B-+sqrt%28+28+%29%29%2F%282%2A1%29 Combine like terms in the radicand (everything under the square root)



x+=+%28-4+%2B-+2%2Asqrt%287%29%29%2F%282%2A1%29 Simplify the square root (note: If you need help with simplifying the square root, check out this solver)



x+=+%28-4+%2B-+2%2Asqrt%287%29%29%2F2 Multiply 2 and 1 to get 2

So now the expression breaks down into two parts

x+=+%28-4+%2B+2%2Asqrt%287%29%29%2F2 or x+=+%28-4+-+2%2Asqrt%287%29%29%2F2


Now break up the fraction


x=-4%2F2%2B2%2Asqrt%287%29%2F2 or x=-4%2F2-2%2Asqrt%287%29%2F2


Simplify


x=-2%2Bsqrt%287%29 or x=-2-sqrt%287%29


So these expressions approximate to

x=0.645751311064591 or x=-4.64575131106459


So our solutions are:
x=0.645751311064591 or x=-4.64575131106459

Notice when we graph x%5E2%2B4%2Ax-3, we get:



when we use the root finder feature on a calculator, we find that x=0.645751311064591 and x=-4.64575131106459.So this verifies our answer