SOLUTION: Factorize 15000 in 2 consecutive numbers whose difference is 2

Question 991564: Factorize 15000 in 2 consecutive numbers whose difference is 2

Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Factorize 15000 in 2 consecutive numbers whose difference is 2
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Factoring implies integers.
121*123 = 14883
122*124 = 15128
No integer solution.
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x*(x+2) = 15000

Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=60004 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 121.478569554024, -123.478569554024. Here's your graph:

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Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Take the square root to get in the right neighborhood.

There are no consecutive factors of 15000.
120 and 125 are the factors closest to each other.

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