Question 965596: The sum of two number is 98. If three times the smaller number is subtracted from the larger number, the result is 10. Find the two numbers. Answer by macston(5194) (Show Source):
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S=smaller number; L=larger number
L+S=98
L=98-S Use this to substitute for L
L-3S=10 Substitute for L from above.
98-S-3S=10 Subtract 98 from each side.
-4S=-88 Divide each side by -4
S=22 ANSWER 1: The smaller number is 22.
L=98-S=98-22=76 ANSWER 2: The larger number is 76.
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CHECK:
L-3S=10
76-3(22)=10
76-66=10
10=10