SOLUTION: Carolyn left the study group traveling 6 mph. Then, 3 hours later, Alicia left traveling the same direction at 15 mph. How long until Alicia catches up with Carolyn? How many hours
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Question 950471: Carolyn left the study group traveling 6 mph. Then, 3 hours later, Alicia left traveling the same direction at 15 mph. How long until Alicia catches up with Carolyn? How many hours? Answer by Cody959(5) (Show Source):
You can put this solution on YOUR website! Okay in order for us to solve this problem we need to know a fundamental physic's equation:
This is equation:(*1)
Where:
s=speed
d=distance
t=time
With this equation and using simple algebraic manipulation we can find the distance that Carolyn has traveled; using her speed and the amount of time that has passed.
Knowing how fast Alicia is traveling and how far Carolyn has traveled we can again use simple algebraic manipulation of equation (*1) to find the time Alicia catches Carolyn.
Fun Fact: Equation (*1) is a fundamental idea in calculus and Newtonian physics. Velocity (speed with direction) is defined as:
This is known as a differential equation.
Where ds is defined as the change in position [or displacement]
And dt is defined as the amount of time that passes.
Hence you are doing calculus right now! :p
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