You can put this solution on YOUR website! let x,x+1,x+2,x+4 be the 4 consecutive whole numbers
sum = x+(x+1)+(x+2)+(x+3)
= x+x+1+x+2+x+3
= 4x+6
4x+6 = 2014
4x= 2014-6
4x= 2008
divide with 4 on both sides
so the four numbers are as follows
x= 502
x+1 = 502+1 = 503
x+2 = 504
x+3 = 505
numbers are = 502,503,504,505
sum of digits of all numbers = 5+0+2+5+0+3+5+0+4+5+0+5
=34
Result : 34