SOLUTION: The larger of 2 numbers is 7 less than twice the smaller number. If the sum of the numbers is 47 find both numbers

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Question 932640: The larger of 2 numbers is 7 less than twice the smaller number. If the sum of the numbers is 47 find both numbers

Found 2 solutions by TimothyLamb, ewatrrr:
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
x = larger number
y = smaller number
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x = 2y - 7
x + y = 47
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put the system of linear equations into standard form
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x - 2y = -7
x + y = 47
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copy and paste the above standard form linear equations in to this solver:
https://sooeet.com/math/system-of-linear-equations-solver.php
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solution:
x = larger number = 29
y = smaller number = 18
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Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi
Let x represent the larger. y the smaller
x -2y = -7
2(x + y = 47)
3x = 87
x = 29, the larger. the smaller is 18 %2829+%2B+7%29+%2F2, x +7 = 2y
and...checking
Sum = 47