SOLUTION: Please help with solving this...I can't seem to get the fractional part correct.
One number exceeds another by 5. The sum of their reciprocals equal to 19 divided by the product
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: Please help with solving this...I can't seem to get the fractional part correct.
One number exceeds another by 5. The sum of their reciprocals equal to 19 divided by the product
Log On
Question 91529: Please help with solving this...I can't seem to get the fractional part correct.
One number exceeds another by 5. The sum of their reciprocals equal to 19 divided by the product of the two numbers. Find the two numbers. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Let one of the numbers be "x"; The other number is "x+5"
EQUATION:
1/x + 1/(x+5) = 19/x(x+5)
Multiply thru by x(x+5)
x+5 + x = 19
2x= 14
x = 7 (one of the numbers)
x+5 = 12 (the other number)
==============
Cheers,
Stan H.
(