SOLUTION: Please help me to solve this question : If sum of 4 consecutive multiple of 6 is 125 then what are the consecutive multiples?

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Question 892292: Please help me to solve this question :
If sum of 4 consecutive multiple of 6 is 125 then what are the consecutive multiples?
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be an integer (maybe?).
6n%2B6%28n%2B1%29%2B6%28n%2B2%29%2B6%28n%2B3%29=125

24n%2B6%2B12%2B18=125
24n%2B36=125
24n=125-36
24n=89
n=89%2F24
n is NOT an integer.

The four multiples of six are 89/4, ....
No. I am stopping there.
Are you SURE you have the correct problem description? What do you mean by "consecutive multiples"? Does each multiple of 6 differ by 1? If so, then the next or last three numbers are 6%2889%2F24%2B1%29, 6%2889%2F24%2B2%29, and 6%2889%2F24%2B3%29.