SOLUTION: find four consecutive integers with a suum of 196

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Question 867110: find four consecutive integers with a suum of 196
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!


Hi

n + (n+1)+(n+2)+(n+3) = 196   

      4n + 6 = 196  

          4n = 190

           n = 47.5   There are NONE