Question 864578: find three consecutive odd integers such that twice the sum of the first two 11 is more than three times greater Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the numbers be x , x+2, x+4
twice the sum of first two
2(x+x+2)
2(2x+2)=3(x+4)+11
4x+4=3x+12+11
4x+4=3x+23
4x-3x=23-4
x=19
19,21,23