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Question 815717: [ Three times the least of three consecutive odd INTEGERS exceeds twice the greatest by 17. Find the three Integers. ]
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! 3i = 2k + 17
k = i + 4
j = i + 2
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3i = 2k + 17
3i = 2(i + 4) + 17
3i = 2i + 8 + 17
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i = 25
j = 27
k = 29
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