Question 800250: how do you find five consecutive odd integers such that the sum of the first and the fifth is one less than three times the fourth Answer by tommyt3rd(5050) (Show Source):
You can put this solution on YOUR website! consecutive integer will be these...
1:n
2:n+2
3:n+4
4:n+6
5:n+8
n + (n+8) = 3(n+6)-1
2n+8=3n+18-1
-n=17-8
n=-9
they are...
-9, -7, -5, -3, -1