SOLUTION: A two digit number in base ten is equal to five times the sum of the digits. It is nine less than the number formed by interchanging the digits. Find the number.
Algebra ->
Customizable Word Problem Solvers
-> Numbers
-> SOLUTION: A two digit number in base ten is equal to five times the sum of the digits. It is nine less than the number formed by interchanging the digits. Find the number.
Log On
Question 759473: A two digit number in base ten is equal to five times the sum of the digits. It is nine less than the number formed by interchanging the digits. Find the number. Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! A two digit number in base ten is equal to five times the sum of the digits. It is nine less than the number formed by interchanging the digits. Find the number.
***
let u=units digit
let t=tens digit
..
10t+u=5(t+u)
10t+u=10u+t-9
..
10t+u=5t+5u
10t+u=10u+t-9
..
5t=4u
t=4u/5
..
10(4u/5)+u=10u+4u/5-9
8u+u=10u+4u/5-9
u+4u/5=9
5u+4u=45
9u=45
u=5
t=4u/5=4
number=45
(