SOLUTION: let the digits of a three digit number be x,y and z. Then the value of the number is 100x+ 10y + x. Show that the difference between the number and reversed number is 99
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Question 724253: let the digits of a three digit number be x,y and z. Then the value of the number is 100x+ 10y + x. Show that the difference between the number and reversed number is 99 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! let the digits of a three digit number be x,y and z. Then the value of the number is 100x+ 10y + z. Show that the difference between the number and reversed number is 99
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reversed number: 100z + 10y + x
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Equation:
(100x+ 10y + z) - (100z + 10y + x) = 99x - 99z = (99)(x-z)
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Example:
586 - 685 = -101
200-002 = 198
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Note: The claim made is not true as stated.
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Cheers,
Stan H.
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