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Question 719519: Find three consecutive integers such that the sum of the first and third is 63.
Answer by lenny460(1073)   (Show Source):
You can put this solution on YOUR website! Find three consecutive integers such that the sum of the first and third is 63.
Let the three consecutive integers be:
n + (n + 1) + (n + 2)
Add the first and third:
n + n + 2 = 63
2n + 2 = 63
Subtract 2 from each side of the equation:
2n + 2 - 2 = 63 - 2
Combine like terms:
2 - 2 = 0
63 - 2 = 61
Therefore:
2n = 61
Divide each side by 2
2n/2 = 61/2
n = 30.5
n + 1 = 31.5
n + 2 = 32.5
Therefore the first and third add up to 63
n + n + 2 = 30.5 + 32.5 = 63
Therefore the three consecutive integers are:
30.5, 31.5 and 32.5
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