SOLUTION: There are 73 children at the playground. 1/3 of the boys and 2/7 of the girls are swimming in the pool. If there are 22 kids in the pool in all, how many boys are there at the pl
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Question 711438: There are 73 children at the playground. 1/3 of the boys and 2/7 of the girls are swimming in the pool. If there are 22 kids in the pool in all, how many boys are there at the playground? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! There are 73 children at the playground.
b + g = 73
g = (73-b)
1/3 of the boys and 2/7 of the girls are swimming in the pool.
If there are 22 kids in the pool in all, b + g = 22
multiply by 21 to get rid of the denominators, resulting in:
7b + 3(2g) = 21*22
7b + 6g = 462
replace g with (73-b)
7b + 6(73-b) = 462
7b + 438 - 6b = 462
7b - 6b = 462 - 438
b = 24 boys at the playground?
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:
confirm this by finding the number of girls, then the total in the pool.
73 - 24 = 49 girls *24 + *49 =
8 + 14 = 22 in the pool
