SOLUTION: Product of 3 integers equals 56. Second is twice the first and third is five more than first. What three numbers are they?

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Question 709095: Product of 3 integers equals 56. Second is twice the first and third is five more than first. What three numbers are they?
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
Integers a, b, c.
abc=56
b=2a
c=5%2Ba

Looking at those relations for a few seconds, we see b and c are formulas using a but not using other variables. Quickest step to begin is substitute them into the first equation
a%28b%29%28c%29=56
a%282a%29%285%2Ba%29=56
Simplify.
Solve for a. Then deal with b and c.