SOLUTION: y varies jointly as m and the square root of n and inversely as p. y=15 when m=2,n=1, and p=6. find y when m=3,n=4, and p=10

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Question 692536: y varies jointly as m and the square root of n and inversely as p. y=15 when m=2,n=1, and p=6. find y when m=3,n=4, and p=10
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
y varies jointly as m and the square root of n and inversely as p.
y = %28m%2Asqrt%28n%29%29%2Fp
:
y=15 when m=2,n=1, and p=6.
let k = the constant of variation
%28k%28m%2Asqrt%28n%29%29%29%2Fp = y
then replace y, m, n, and p; find k
%28k%282%2Asqrt%281%29%29%29%2F6 = 15
%282k%29%2F6 = 15
2k = 15 * 6
2k = 90
k = 90/2
k = 45
then
y = %2845%28m%2Asqrt%28n%29%29%29%2Fp is our equation
:
find y when m=3, n=4, and p=10
y = %2845%283%2Asqrt%284%29%29%29%2F10
y = %2845%286%29%29%2F10
y = 270%2F10
y = 27