SOLUTION: The product of three whole numbers is 60 and their sum is 13. The numbers are all different and greater than 1. We need to find the three numbers with the detailed working of the s
Algebra.Com
Question 689821: The product of three whole numbers is 60 and their sum is 13. The numbers are all different and greater than 1. We need to find the three numbers with the detailed working of the solution.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Since the sum of the three numbers is 13, either all three numbers are odd, or only one of them is odd.
(prime factorization of )
By associating (putting in brackets) two of those four factors, that product can be split into three greater than 1 factors several ways:
A
B
C
D
We eliminate option D because the three factors are not all different.
I eliminate option A because I need to count on my fingers to add, and since the three factors include only two odd numbers, their sum will be even, and cannot be 13. (You can add if you want).
I have to add for options B and C:
B is not the answer
C is the answer.
RELATED QUESTIONS
The product of two whole numbers is 988 and their sum is 64. What are the two... (answered by Alan3354)
1. The sum of 4 integers is 24 and their product is 945. What are those integers?
2.... (answered by CPhill,greenestamps)
what two whole numbers have a product that is three times greater than their... (answered by edjones)
the difference of two numbers greater than 1 is 11, and their product is... (answered by sachi)
The sum of the reciprocals of two numbers is 4/15 and their product is 60. what are the... (answered by mananth)
Two integers are randomly selected from the set of integers greater than or equal to -6... (answered by Edwin McCravy)
A set of five different counting numbers sum to 25. The product of the five numbers in... (answered by dfrazzetto)
if m and n are both negative numbers , m is less than -1 and n is greater than... (answered by Theo)
The sum of three numbers is 27 and their product is 585. Find the... (answered by Alan3354)