SOLUTION: Find three consecutive integers such that the product of the first and the third is 35 greaters than the product of the second and 5.

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Question 68588This question is from textbook An Incremental Development
: Find three consecutive integers such that the product of the first and the third is 35 greaters than the product of the second and 5. This question is from textbook An Incremental Development

Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
X(X+2)=35+5(X+1)
X^2+2X=35+5X+5
X^2+2X-5X-35-5=0
X^2-3X-40=0
(X-8)(X+5)=0
X-8=0
X=8 ANSWER
PROOF
8*10=35+5(9)
80=35+45
80=80
--------------------------
X+5=0
X=-5 ANSWER
PROOF
-5*-3=35+5(-4)
15=35-20
15=15