SOLUTION: two consecutive integers are such that three times the first integer is 15 more than the second integer. find the integers

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Question 678556: two consecutive integers are such that three times the first integer is 15 more than the second integer. find the integers
Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
x x+1
...
3x = 15+x+1
3x = 16 +x
3x - x = 16
2x = 16
x = 8
...
Integers are 8 and 9
...
Check
3(8) = 24
15 + 8 + 1 = 24
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