SOLUTION: Using two even consecutive integers where two times the lower integer plus the higher integer equals 50.
I have tried: 2x2+4=8, 4x4+6=22, 6x6+8=44, 8x8+10=64 so I can get close
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I have tried: 2x2+4=8, 4x4+6=22, 6x6+8=44, 8x8+10=64 so I can get close
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Question 674562: Using two even consecutive integers where two times the lower integer plus the higher integer equals 50.
I have tried: 2x2+4=8, 4x4+6=22, 6x6+8=44, 8x8+10=64 so I can get close but not equal to 50 without going over Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Using two even consecutive integers where two times the lower integer plus the higher integer equals 50.
.
Let x = lower even integer
then
x+2 = higher consecutive even integer
.
2x + (x+2) = 50
3x + 2 = 50
3x = 48
x = 16 (lower)
.
higher:
x+2 = 16+2 = 18
.
answer: 16 and 18