SOLUTION: find two consecutive odd numbers whose square of the larger number is 208 more than nine times the smaller number

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Question 663703: find two consecutive odd numbers whose square of the larger number is 208 more than nine times the smaller number
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
find two consecutive odd numbershighlight%28x%29andhighlight%28x%2B2%29 whose square of the larger number
is 208 more than nine times the smaller number
Translating into an equation***
(x+2)^2 = 9x + 208
x^2 + 4x + 4 = 9x + 208
x^2 - 5x - 204 = 0 ||factor or use the Quadratic formula x+=+%285+%2B-+sqrt%28+841+%29%29%2F%282%29+
(x-17)(x+12) = 0 , x = 17 (throwing out negative even number -12)
The two consecutive odd numbers are 17, 19
and...
19%5E2+=+9%2A17+%2B+208=+361
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