SOLUTION: what are solutions to the equation ? *have to be square roots ! (2x+3)^2=10

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Question 627424: what are solutions to the equation ? *have to be square roots !
(2x+3)^2=10
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%282x%2B3%29%5E2=10 Start with the given equation.


2x%2B3=%22%22%2B-sqrt%2810%29 Take the square root of both sides.


2x%2B3=sqrt%2810%29 or 2x%2B3=-sqrt%2810%29 Break up the "plus/minus" to form two equations.


2x=-3%2Bsqrt%2810%29 or 2x=-3-sqrt%2810%29 Subtract 3 from both sides.


x=%28-3%2Bsqrt%2810%29%29%2F2 or x=%28-3-sqrt%2810%29%29%2F2 Divide both sides by 2.


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Answer:


So the solutions are x=%28-3%2Bsqrt%2810%29%29%2F2 or x=%28-3-sqrt%2810%29%29%2F2.

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