SOLUTION: the sum of two integers is 8. The sum of the squares of the intgers in 50. Use algebra to solve for the two integers.

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Question 610688: the sum of two integers is 8. The sum of the squares of the intgers in 50. Use algebra to solve for the two integers.
Answer by Maths68(1474) About Me  (Show Source):
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Let x, and y be the two integers
The sum of two integers is 8
x%2By=8
x=8-y...........(1)
The sum of the squares of the intgers in 50
x%5E2%2By%5E2=50.........(2)
substitute the value of x from (1) to (2)
%288-y%29%5E2%2By%5E2=50
64-16y%2By%5E2%2By%5E2=50
64-16y%2B2y%5E2=50
64-16y%2B2y%5E2-50=0
14-16y%2B2y%5E2=0
2%287-8y%2By%5E2%29=0
2%287-8y%2By%5E2%29%2F2=0%2F2
cross%282%29%287-8y%2By%5E2%29%2Fcross%282%29=0
7-8y%2By%5E2=0
y%5E2-8y%2B7=0
Solve for y
y%5E2-7y-y%2B7=0
y%28y-7%29-1%28y%2B7%29=0
%28y-7%29%28y-1%29=0
y-7=0 or y-1=0
y=7 or y=1
Put the values of y in (1)
x=8-y
y=1
x=8-1
x=7
y=7
x=8-y
x=8-7
x=1
So,
Integers are 1,7 or 7,1