SOLUTION: three times a first number decreased by a second number is 22the first number increased by twice the second number is 19

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Question 602451: three times a first number decreased by a second number is 22the first number increased by twice the second number is 19
Answer by ewatrrr(24785) About Me  (Show Source):
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Hi,

Let x be the first number and y represent the second number:

Writing as we read:

 3x - y  = 22

  x + 2y = 19

Solving by elimination:

 6x - 2y  = 44   |mutiplying first EQ by 2 to eliminate y

  x + 2y  = 19

      7x =  63

       x = 9   |3x - y  = 22 OR 3x-22 = y , y = 3*9 - 22 = 5