SOLUTION: Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers.

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Question 586274: Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find 4 consecutive odd integers where the product of the two smaller numbers is 64 less than the product of the two larger numbers.
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1st: 2x-3
2nd: 2x-1
3rd: 2x+1
4th: 2x+3
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Equation:
(2x-3)(2x-1) = (2x+1)(2x+3)-64
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4x^2-8x+3 = 4x^2+8x+3 - 64
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-16x = -64
x = 4
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1st: 2x-3 = 5
2nd: 7
3rd: 9
4th: 11
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Cheers,
Stan H.
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