SOLUTION: Find three consecutive integers such that the first plus three times the third is 10 less than three times the second.

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Question 562796: Find three consecutive integers such that the first plus three times the third is 10 less than three times the second.
Answer by Maths68(1474) About Me  (Show Source):
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Let
First Number = x%2B1
Second Number=x%2B2
Third Number = x%2B3
x%2B1%2B3%28x%2B3%29=3%28x%2B2%29-10
x%2B1%2B3x%2B9=3x%2B6-10
4x%2B10=3x%2B6-10
4x=3x%2B6-10-10
4x=3x%2B6-20
4x-3x=-14
x=-14

First Number = x%2B1 = -14%2B1 = -13
Second Number=x%2B2 = -14%2B2 = -12
Third Number = x%2B3 = -14%2B3 = -11