SOLUTION: Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91. Thank you so much!!!!! Kelli

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Question 53220: Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.

Thank you so much!!!!!
Kelli
Answer by venugopalramana(3286) About Me  (Show Source):
You can put this solution on YOUR website!
Find four consecutive integers such that twice the sum of the two greater integers exceeds three times the first by 91.
LET N,N+1,N+2,N+3 BE THE 4 INTEGERS
SUM OF 2 GREATER INTEGERS = N+2+N+3=2N+5
TWICE THE SUM = 2(2N+5)=4N+10
3 TIMES THE FIRST = 3N
4N+10=3N+91
N=81
SO THE 4 INTEGERS ARE 81,82,83,84