SOLUTION: find three consecutive odd integer such that 3 times the middle integer is 7 more than the sum of the first and third integer

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Question 52058: find three consecutive odd integer such that 3 times the middle integer is 7 more than the sum of the first and third integer
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Calling a number 2n + 1, where n is any integer guarantees
that 2n + 1 will be odd
Call the 3 successive odd integers
2n+%2B+1,2n+%2B+3,2n+%2B+5
3%2A%282n+%2B+3%29+=+7+%2B+%282n+%2B+1%29+%2B+%282n+%2B+5%29
6n+%2B+9+=+7+%2B+4n+%2B+6
2n+=+13+-+9
2n+=+4
n+=+2
2n+%2B+1+=+5
2n+%2B+3+=+7
2n+%2B+5+=+9
The 3 successive odd numbers are 5,7,9
check
3%2A%282n+%2B+3%29+=+7+%2B+%282n+%2B+1%29+%2B+%282n+%2B+5%29
3%2A7+=+7+%2B+5+%2B+9
21+=+12+%2B+9
21+=+21
OK