SOLUTION: The tens digit is 5 more than the unit digit. If the sum of their squares is 53, find the number.

 

Hi,

The tens digit is 5 more than the unit digit

let x and (x+5) represent the unit's and ten's digits respectively

Question states***

 x^2 + (x+5)^2 = 53

 2x^2 + 10x - 28 = 0

 x^2 + 5x - 14 = 0 

factoring

(x+7)(x-2) = 0

(x+7)= 0  x = -7  tossing out negative number for a digit amount

(x-2) = 0 x = 2, one's digit, ten digit is 7.  Number is 72.



CHECKING our Answer***

 2^2 + 7^2 = 4 + 49 = 53