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Question 463052: I am the largest 5-digit number you can make that has all odd digits. My ten thousands digit is thrice my ones digit. My thousands digit is two more than my hundreds digit. What number am I?
Pls answer ^_^ Thank you
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! the largest 5 digit number that you can have when all digits are odd would be 99999.
that's with no restrictions.
any other number you choose would have to be smaller.
the restrictions are:
the ten thousands digits is 3 times the ones digit.
since the ten thousands digit is fixed at 9, then the ones digit has to be 3 because 3 * 3 = 9.
the thousands digit is 2 more than the hundreds digit.
since the thousands digit is fixed at 9, then the hundreds digit has to be 7 because 7 + 2 = 9.
that makes your number equal to 99793.
any other arrangement would force the ten thousands digit to be something less than 9 or the thousands digit to be less than 9 which would result in a smaller number.
an example:
your number is 99793.
suppose you made the hundreds digit 5. this would force the thousands digit to be equal to 7 which would make your number 97593 which is smaller than 99793.
similarly, your number is 99793.
suppose you made the units digit equal to 1. this would force the ten thousands digit to be equal to 3 which would make your number 39791 which is smaller than 99793.
your ones digit can't be greater than 3 because then your ten thousands digit would be greater than 9 which it can't be (each digit can only be 0 to 9).
your hundreds digit can't be greater than 7 for the same reason.
bottom line is, the greatest number you can get, given the restrictions, is 99793.
the ten thousands digit is 3 times the units digit.
the thousands digit is 2 more than the hundreds digit.
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