|
Question 433911: HEY! can you help me figure out this digit problem?? Im stuck at the end result and need some help...Thanks!!
The value of a certain two-digit number is 9 times the sum of its digits. If the digits are reversed, the resulting number is 63 less than the original number. Find the original number.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The value of a certain two-digit number is 9 times the sum of its digits. If the digits are reversed, the resulting number is 63 less than the original number. Find the original number.
----------------
Equations:
10t+u = 9(t+u)
10u+t = (10t+u)-63
-------------------------
Rearrange:
t = 8u
9u-9t = -63
-------------------
t = 8u
u-t = -7
----
Substitute for "t" ans solve for "u":
u-8u = -7
-7u = -7
u = 1
---
Solve for "t":
t = 8*1
t = 8
---
Original Number: 10t+u = 81
===============================
Cheers,
Stan H.
============
|
|
|
| |
