You can put this solution on YOUR website! find two consecutive even integers such that twice the first plus twice the second is 116
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1st: 2x
2nd: 2x+2
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Equation:
2(2x)+2(2x+2) = 116
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4x + 4x+4 = 116
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8x = 112
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x = 14
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1st: 2x = 28
2nd: 2x+2 = 30
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Cheers,
Stan H.