SOLUTION: find three consecutive even integers such that three times the first plus twice the third is 248.

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Question 397741: find three consecutive even integers such that three times the first plus twice the third is 248.
Answer by unlockmath(1688) About Me  (Show Source):
You can put this solution on YOUR website!
Hello,
We can show these as x, x+2, x+4
Now we can set up an equation as:
3x + 2(x+4)= 248
Combine like terms:
5x+8=248
Subtract 8 and divide by 5 both sides:
x=48
So now we know the integers are 48,50,52
Make sense?
RJ
www.math-unlock.com