SOLUTION: Find two consecutive integers such that 1/3 the smaller plus twice the larger equals 7 more than the sum of the two numbers.

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Question 338424: Find two consecutive integers such that 1/3 the smaller plus twice the larger equals 7 more than the sum of the two numbers.
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
Let the numbers be x and x+1.
x/3 + 2(x+1)=x+x+1+7
x/3 + 2x+2=2x+8
x/3=6
x=18
.
Ed