SOLUTION: If w,x,y and z are non negative integers, each less than 3, and w(33) + x(32) + y(3) + z = 34, then w+z= Can you please solve the above question. Would really appreciate.

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: If w,x,y and z are non negative integers, each less than 3, and w(33) + x(32) + y(3) + z = 34, then w+z= Can you please solve the above question. Would really appreciate.       Log On

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Question 336626: If w,x,y and z are non negative integers, each less than 3, and w(33) + x(32) + y(3) + z = 34, then w+z=

Can you please solve the above question. Would really appreciate.

Thanks
Sarah
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Since x,y,z,and w are non-negative integers less than 3, they can have values of 0,1,or 2.


33w%2B32x%2B3y%2Bz=34


Let's look at all possible values.
If w=0, then x=1, and z=2 and y=0, since 32%2B0%2B0%2B2=34, w%2Bz=2
If w=1, then z=1 and x=y=0 since 33%2B0%2B0%2B1=34, w%2Bz=2
If w=2, w can't equal 2 because 33%282%29=66%3E34.
Those are all of the possible solutions.
So, highlight%28w%2Bz=2%29.