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Question 327329: The sum of the digits of a three digit number is 19. The hundreds digit is three times the tens digit. the number is 198 more than the number reversed. find the original number.
Answer by galactus(183) (Show Source):
You can put this solution on YOUR website! Think it through. If the 100's digit is 3 times the tens digit, there are a few candidates we can have.
Let the 10's digit be 3. Then, since the 100's digit is 3 times that, it must be 9. The 3 digits sum to 19, so the 1's digit must be 7.
So, we have 937. Reverse this and we have 739. Which is 198 less than 937.
Check.
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