SOLUTION: Jesse doubled a number and then added 5 to get 4l. If he had first added 5
to the original number and then doubled the result, the answer would have been
(a) 18 (b 41 c)
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-> SOLUTION: Jesse doubled a number and then added 5 to get 4l. If he had first added 5
to the original number and then doubled the result, the answer would have been
(a) 18 (b 41 c)
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Question 288276: Jesse doubled a number and then added 5 to get 4l. If he had first added 5
to the original number and then doubled the result, the answer would have been
(a) 18 (b 41 c) 46 (d) 49 (e) 92
You can put this solution on YOUR website! Let's call the original number A:
Double the original number (A), and add 5 to it to gain 41:
2A + 5 = 41
2A = 41 - 5
2A = 36 A = 18
.
So now that we know the value of A, we can find the value asked by the problem:
.
Add 5 to A, then double the result:
.
(A + 5)*2 = (18 + 5)*2 = 23*2 = 46 (c)
