SOLUTION: find 3 consecutive integers, the sum of whose squares is 29 more then 3 times the square of the smallest
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Question 284237
:
find 3 consecutive integers, the sum of whose squares is 29 more then 3 times the square of the smallest
Answer by
nyc_function(2741)
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Let x = first integer
Let x + 1 = second integer
Let x + 2 = third integer
x^2 + (x + 1)^2 + (x + 2)^2 = x^2 + 29
This is your equation.
Can you finish now?