SOLUTION: The product of two consecutive positive integers is 109 more than their sum. Find the integers.
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Question 284079
:
The product of two consecutive positive integers is 109 more than their sum. Find the integers.
Answer by
checkley77(12844)
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X(X+1)=X+X+1+109
X^2+X=2X+110
X^2+X-2X-110=0
X^2-X-110=0
(X-11)(X+10=0
X-11=0
X=11 ANS
X+10=0
X=-10 ANS.
PROOF:
11(11+1)=11+12+109
11*12=132
132=132