Question 282671: Find three consecutive odd integers such that the sum of the first, two times the second, and three times the third is 70. Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! let the integers be x, x+2, and x+4
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70
6x+16=70
6x=70-16
6x=54
x=9
the numbers are 9,11,13