Question 271640: A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number. Answer by dabanfield(803) (Show Source):
You can put this solution on YOUR website! A two-digit number is five times the sum of its digits. The digits from left to right name consecutive integers. Find the number.
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Let x be the tens digit. Then the ones digit is the next consecutive integer or x+1.
The number then is 10*x + 1*(x+1).
So we have:
10*x + 1*(x+1) = 5*((x + (x + 1))
10x + x + 1 = 5*(2x + 1)
11x + 1 = 10x + 5
Solve the above for x and then calculate x+1.